Henrik Sönnerlind
COMSOL Employee
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Posted:
6 years ago
Jun 15, 2018, 1:40 a.m. EDT
Hi,
If you introduce the pore pressure using the Pore pressure option in External Stress, then it is not part of the the stress computation (it only acts as a volumetric load contribution). That is, the stress you see as for example solid.s is the the stress in the matrix of the porous material, also known as the effective stress tensor.
Regards,
Henrik
-------------------
Henrik Sönnerlind
COMSOL
Hi,
If you introduce the pore pressure using the *Pore pressure* option in *External Stress*, then it is not part of the the stress computation (it only acts as a volumetric load contribution). That is, the stress you see as for example *solid.s* is the the stress in the matrix of the porous material, also known as the effective stress tensor.
Regards,
Henrik
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Posted:
6 years ago
Jun 18, 2018, 11:56 a.m. EDT
Thanks Henrik for replying me back. If I want to see the effect of pore pressure on static stress analysis, should I define pore pressure as a diagonal stress tensor? or I should define my in situ stress tensor as effective stress tensor?
Thanks Henrik for replying me back. If I want to see the effect of pore pressure on static stress analysis, should I define pore pressure as a diagonal stress tensor? or I should define my in situ stress tensor as effective stress tensor?
Henrik Sönnerlind
COMSOL Employee
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Posted:
6 years ago
Jun 19, 2018, 11:23 a.m. EDT
Hi,
You will see the efffect of pore pressure irrespective of if you add it as 'Pore pressure' or just as a diagonal tensor. The displacements will be the same, but in the first case the stress is 'effective', whereas in the second case it is 'total'.
If, however, you change 'Contribution type' to 'Load contribution only', then you get exacly the same results as with 'Pore pressure', that is an effective stress.
Regards,
Henrik
-------------------
Henrik Sönnerlind
COMSOL
Hi,
You will see the efffect of pore pressure irrespective of if you add it as 'Pore pressure' or just as a diagonal tensor. The displacements will be the same, but in the first case the stress is 'effective', whereas in the second case it is 'total'.
If, however, you change 'Contribution type' to 'Load contribution only', then you get exacly the same results as with 'Pore pressure', that is an effective stress.
Regards,
Henrik
Please login with a confirmed email address before reporting spam
Posted:
6 years ago
Jun 22, 2018, 1:44 p.m. EDT
I highly appreciate you for giving me such a helpful information.
I highly appreciate you for giving me such a helpful information.