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Plane symmetry /// Solid Mechanics Module

Posted Jan 17, 2020, 12:03 p.m. EST Structural Mechanics Version 5.0 4 Replies

Hossein Babaei
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Hi there,

I have a 3D model with a symmetry plane. I cannot find any boundary condition in my COMSOL's 5.0 Solid Mechanics module for symmetry. Am I missing it, or the symmetry boundary condition is forced by other available conditions indirectly?

Please help with this.

Cheers, Hossein

4 Replies Last Post Jan 21, 2020, 10:17 a.m. EST
Sergei Yushanov Certified Consultant
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Posted: 5 years ago Jan 17, 2020, 12:28 p.m. EST

Hossein,

Symmetry BC is under More Constraints, as shown in the attached image.

Regards,

Sergei

Hossein, Symmetry BC is under More Constraints, as shown in the attached image. Regards, Sergei

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Hossein Babaei
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Posted: 5 years ago Jan 17, 2020, 12:47 p.m. EST

Dear Sergei,

Thanks for your quick response. My COMSOL v5.0 doesn't seem to have "More Constrains". Please see the attached. Could be hidden?

Thanks, Hossein

Dear Sergei, Thanks for your quick response. My COMSOL v5.0 doesn't seem to have "More Constrains". Please see the attached. Could be hidden? Thanks, Hossein
Henrik Sönnerlind COMSOL Employee

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Posted: 5 years ago Jan 20, 2020, 2:19 a.m. EST

Hi Hossein,

The specialized boundary conditions under More Constraints are only present if you have the Structural Mechanics Module license. If not, you will have to express the boundary condition using the Prescribed Displacement node.

Regards,
Henrik

-------------------
Henrik Sönnerlind
COMSOL
Hi Hossein, The specialized boundary conditions under More Constraints are only present if you have the Structural Mechanics Module license. If not, you will have to express the boundary condition using the Prescribed Displacement node. Regards, Henrik
Hossein Babaei
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Posted: 5 years ago Jan 21, 2020, 10:17 a.m. EST

Dear Henrik,

Thank you, I forced the symmetric boundary condition by using the Prescribed Displacement node, forcing zero out-of-symm.-plane displacement, and not imposing any other boundary condition on the symm. plane.

Cheers, Hossein

Dear Henrik, Thank you, I forced the symmetric boundary condition by using the Prescribed Displacement node, forcing zero out-of-symm.-plane displacement, and not imposing any other boundary condition on the symm. plane. Cheers, Hossein

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