Edgar J. Kaiser
Certified Consultant
Please login with a confirmed email address before reporting spam
Posted:
3 years ago
Apr 8, 2022, 2:04 p.m. EDT
Updated:
3 years ago
Apr 8, 2022, 2:06 p.m. EDT
Christophe,
maybe the easiest solution is to make one of the electrodes to ground, the other electrode to +9V and let the former ground structure float.
Cheers
Edgar
-------------------
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
Christophe,
maybe the easiest solution is to make one of the electrodes to ground, the other electrode to +9V and let the former ground structure float.
Cheers
Edgar
Please login with a confirmed email address before reporting spam
Posted:
3 years ago
Apr 8, 2022, 2:16 p.m. EDT
There are probably some other workarounds, say using the circuit module and some 1E12 ohm resistors.
But I suggest thinking about whether this corresponds to the real experimental situation, as sources tend to have some sort of connection to ground through parasitics.
There are probably some other workarounds, say using the circuit module and some 1E12 ohm resistors.
But I suggest thinking about whether this corresponds to the real experimental situation, as sources tend to have some sort of connection to ground through parasitics.
Please login with a confirmed email address before reporting spam
Posted:
3 years ago
Apr 8, 2022, 9:46 p.m. EDT
Hi,
thanks for your suggestions but the apparatus is installed on a aerial electric line and not connected to ground, Inside this apparatus, a 9v batterie is connected to two electrodes acting like a capacitor. I want to simulate the E-field response inside the apparatus et consequently model the applied voltage of the battery which is a floating voltage.
Hi,
thanks for your suggestions but the apparatus is installed on a aerial electric line and not connected to ground, Inside this apparatus, a 9v batterie is connected to two electrodes acting like a capacitor. I want to simulate the E-field response inside the apparatus et consequently model the applied voltage of the battery which is a floating voltage.
Edgar J. Kaiser
Certified Consultant
Please login with a confirmed email address before reporting spam
Posted:
3 years ago
Apr 9, 2022, 3:11 a.m. EDT
Then my suggestion should be appropriate. It will provide accurate fields.
-------------------
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
Then my suggestion should be appropriate. It will provide accurate fields.
Please login with a confirmed email address before reporting spam
Posted:
3 years ago
Apr 11, 2022, 3:04 p.m. EDT
Thanks Edgar foe your suggestions. However, the appratus must be submitted to the external E-fields resulting from the power line, E-field which is establissed between the bare conductor and the ground (earth). In my understanding, the ground in Comsol in the same for all bondaries?
Best reagards.
Thanks Edgar foe your suggestions. However, the appratus must be submitted to the external E-fields resulting from the power line, E-field which is establissed between the bare conductor and the ground (earth). In my understanding, the ground in Comsol in the same for all bondaries?
Best reagards.
Edgar J. Kaiser
Certified Consultant
Please login with a confirmed email address before reporting spam
Posted:
3 years ago
Apr 11, 2022, 3:26 p.m. EDT
Ground is on the boundaries you apply it to. It is only a different word for a 0V potential. In any computer model you need to apply a defined potential to at least one point. That is how potential fields work. This setting can be ground (0V) or any other appropriate potential value.
-------------------
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
Ground is on the boundaries you apply it to. It is only a different word for a 0V potential. In any computer model you need to apply a defined potential to at least one point. That is how potential fields work. This setting can be ground (0V) or any other appropriate potential value.