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Prescribed displacement as function of space in structural mechanics stationary study

Posted Jun 18, 2023, 11:29 a.m. EDT Structural Mechanics Version 6.1 4 Replies

Jane Kelleher
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Hello,

I have a question about spatially varying prescribed displacements. I have a bar geometry of length L, and I would like to prescribe its displacement as a function along the length, e.g. Ydisp = sin(pix/L) I tried 1) Directly typing this function of x and the parameter L into the prescribed displacement expression 2) Creating a globally defined analytical function, an1 = sin(pix/L), and then setting the prescribed displacement expression to an1(x)

However, both attempts give non-sensical solutions. What is the correct method to define a prscribed displacement as a function of space?

Thank you very much,

JT

4 Replies Last Post Jun 21, 2023, 6:35 a.m. EDT
Edgar J. Kaiser Certified Consultant
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Posted: 1 year ago Jun 18, 2023, 1:19 p.m. EDT

The syntax has to be sin(pi*x/L)

-------------------
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
The syntax has to be sin(pi*x/L)
Jane Kelleher
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Posted: 1 year ago Jun 19, 2023, 2:37 a.m. EDT

Hi Edgar,

Thanks for your reply! Apologies, that was just poor syntax in my post. I did include the asterisk, i.e. sin(pi*x/L). Was it correct to enter this into the prescribed displacement expression, directly? If so, I must be making an error elsewhere...

Thank you,

Jane

Hi Edgar, Thanks for your reply! Apologies, that was just poor syntax in my post. I did include the asterisk, i.e. sin(pi*x/L). Was it correct to enter this into the prescribed displacement expression, directly? If so, I must be making an error elsewhere... Thank you, Jane
Edgar J. Kaiser Certified Consultant
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Posted: 1 year ago Jun 19, 2023, 3:27 a.m. EDT

That is correct.

-------------------
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
That is correct.
Jane Kelleher
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Posted: 1 year ago Jun 21, 2023, 6:35 a.m. EDT

Thanks very much, Edgar!

Jane

Thanks very much, Edgar! Jane

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