Acculution ApS
Certified Consultant
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Posted:
10 months ago
Jan 21, 2024, 8:23 a.m. EST
Start out with a frequency domain study (steady-state). Your frequency is seemingly 60 Hz, so that is what you input. Then go to a time-domain study.
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René Christensen, PhD
Acculution ApS
www.acculution.com
info@acculution.com
Start out with a frequency domain study (steady-state). Your frequency is seemingly 60 Hz, so that is what you input. Then go to a time-domain study.
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Posted:
10 months ago
Jan 21, 2024, 4:04 p.m. EST
Updated:
10 months ago
Jan 21, 2024, 4:04 p.m. EST
that correct my frequency is 60 Hz so i need to do a
- frequency domain, then using the result use
- frequency to time domain as the next step?
that correct my frequency is 60 Hz so i need to do a
1. frequency domain, then using the result use
2. frequency to time domain as the next step?
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Posted:
10 months ago
Jan 21, 2024, 7:20 p.m. EST
Updated:
10 months ago
Jan 21, 2024, 7:12 p.m. EST
Frequency dependent gets you the sinusoidal steady state solution.
Time dependent with sin(wt) gets you the initial transient when the sinusoidal excitation is turned on at t = 0.
Which one do you want??
Frequency dependent gets you the sinusoidal steady state solution.
Time dependent with sin(wt) gets you the initial transient when the sinusoidal excitation is turned on at t = 0.
Which one do you want??
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Posted:
10 months ago
Jan 22, 2024, 4:33 p.m. EST
Updated:
10 months ago
Jan 22, 2024, 4:25 p.m. EST
when t = 0
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Posted:
10 months ago
Jan 22, 2024, 6:13 p.m. EST
Updated:
10 months ago
Jan 22, 2024, 6:06 p.m. EST
OK if you are doing a time-dependent study then t is automatically time and the driving function should be written 200[um]sin(2pi60[1/s]t).
(If you do a frequency dependent study all quantities are phasors and time does not explicitly appear.)
(The website seems to remove asterisks from equations so you need to put them where they belong).
OK if you are doing a time-dependent study then t is automatically time and the driving function should be written 200[um]*sin(2*pi*60[1/s]*t).
(If you do a frequency dependent study all quantities are phasors and time does not explicitly appear.)
(The website seems to remove asterisks from equations so you need to put them where they belong).
Henrik Sönnerlind
COMSOL Employee
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Posted:
10 months ago
Jan 23, 2024, 2:15 a.m. EST
Updated:
10 months ago
Jan 23, 2024, 8:41 a.m. EST
A comment on the formatting: The forum uses the 'Markdown' syntax. Asterisk then means italic. If you want the asterisk to be shown as is, put a backslash ( \ ) in front of it. For more details, see https://www.comsol.com/forum/formatting-guide
The expression should then look like 200[um]*sin(2*pi*60[1/s]*t).
Entered as
200[um]\*sin(2\*pi\*60[1/s]\*t)
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Henrik Sönnerlind
COMSOL
A comment on the formatting: The forum uses the 'Markdown' syntax. Asterisk then means *italic*. If you want the asterisk to be shown as is, put a backslash ( \ ) in front of it. For more details, see
The expression should then look like 200[um]\*sin(2\*pi\*60[1/s]\*t).
Entered as
200[um]\*sin(2\*pi\*60[1/s]\*t)