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Deformation in a Tire
Posted Apr 27, 2013, 12:47 p.m. EDT Modeling Tools & Definitions, Parameters, Variables, & Functions, Structural Mechanics Version 4.3, Version 4.3a 1 Reply
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Hi everyone,
I am currently trying to model a tire going over a ledge and examining the stresses and deformation caused by the impact of the ledge with the tire. I am applying applying 5000 N of force that is dependent on the location of the ledge. In other words, the force in the x direction is 5000*cos(theta) in the x direction and 5000*sin(theta) in the z direction, where theta varies between 220 and 270 degrees. There is also an internal pressure being applied of 70 psi.
I am having trouble actually getting the deformation to occur. The force is applied in the area where the ledge meets the tire, but no deformation actually occurs.
If you need more information I will gladly provide it. Any insight is greatly appreciated.
Thanks
The attached picture is one of the results I am getting. A force is applied in that small cut-out region that represent where the ledge meets the tire. As shown, stresses are caused by the force, but no deformation occurs. The inside part of the tire has a fixed constraint on it, which is where the metal would be on a real tire.
I am currently trying to model a tire going over a ledge and examining the stresses and deformation caused by the impact of the ledge with the tire. I am applying applying 5000 N of force that is dependent on the location of the ledge. In other words, the force in the x direction is 5000*cos(theta) in the x direction and 5000*sin(theta) in the z direction, where theta varies between 220 and 270 degrees. There is also an internal pressure being applied of 70 psi.
I am having trouble actually getting the deformation to occur. The force is applied in the area where the ledge meets the tire, but no deformation actually occurs.
If you need more information I will gladly provide it. Any insight is greatly appreciated.
Thanks
The attached picture is one of the results I am getting. A force is applied in that small cut-out region that represent where the ledge meets the tire. As shown, stresses are caused by the force, but no deformation occurs. The inside part of the tire has a fixed constraint on it, which is where the metal would be on a real tire.
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1 Reply Last Post Apr 29, 2013, 5:07 p.m. EDT