Menu

Discussion Forum

New Discussion
Filter

Note: This discussion is about an older version of the COMSOL Multiphysics® software. The information provided may be out of date.

Discussion Closed This discussion was created more than 6 months ago and has been closed. To start a new discussion with a link back to this one, click here.

Induction heating electromagnetic equation

Posted Jun 20, 2013, 7:16 p.m. EDT Low-Frequency Electromagnetics, Heat Transfer & Phase Change Version 4.3b 2 Replies

Nestor Bolaños Rodriguez
Send Private Message Flag post as spam

Please login with a confirmed email address before reporting spam

Hi, i'm looking at the electromagnetic equation on the induction heating domain and I'm wondering about the terms multiplied by the potential vector. From which equations do they come?
I attached a photo that shows the terms I'm referring to.

Attachments:

2 Replies Last Post Jun 24, 2013, 2:57 a.m. EDT
Nestor Bolaños Rodriguez
Send Private Message Flag post as spam

Please login with a confirmed email address before reporting spam

Posted: 1 decade ago Jun 21, 2013, 2:52 p.m. EDT
Any ideas?
Any ideas?
Jens Krause
Send Private Message Flag post as spam

Please login with a confirmed email address before reporting spam

Posted: 1 decade ago Jun 24, 2013, 2:57 a.m. EDT
Hi

you can derive this from Maxwell-equations in potential formulation plus Ohm's law
for time-harmonic fields:

in brief:

j = sigma*E = -sigma * dA/dt = i*omega*sigma*A

The second term is from the displaceemnt current and for electromagnetic waves
that should not influence induction heating.


Jens
Hi you can derive this from Maxwell-equations in potential formulation plus Ohm's law for time-harmonic fields: in brief: j = sigma*E = -sigma * dA/dt = i*omega*sigma*A The second term is from the displaceemnt current and for electromagnetic waves that should not influence induction heating. Jens

Note that while COMSOL employees may participate in the discussion forum, COMSOL® software users who are on-subscription should submit their questions via the Support Center for a more comprehensive response from the Technical Support team.

Suggested Content