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Ramp and Step function

Posted Jul 7, 2014, 2:23 p.m. EDT Low-Frequency Electromagnetics Version 4.3b 3 Replies

Bo Huang
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Hi all,

Does the step1(t[1/s]-10) means that function value becomes 1 after 10 seconds on condition that the step1 is defined as the step function?
Does rm3(t[1/s]-10) means that the function value will increase after 10 seconds with the slope of 1 if the rm3 is defined as the ramp function and the slope setted to be 1?

Thanks all.
3 Replies Last Post Jul 8, 2014, 6:24 a.m. EDT
Pieter Westerik
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Posted: 1 decade ago Jul 8, 2014, 3:25 a.m. EDT
You are right except for the units. You have put [1/s] which equals [Hz]. So it will do the things that you mention after 10 Hz instead of after 10 s.
You are right except for the units. You have put [1/s] which equals [Hz]. So it will do the things that you mention after 10 Hz instead of after 10 s.
HUANG BO
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Posted: 1 decade ago Jul 8, 2014, 6:22 a.m. EDT

if I want to using the 1[V] *step1(t[1/s]-10) to realize the function of increasing to 1[V] after 10 seconds rather than 10 Hz , how could I change the formula? If I put the formula 1[V]*step1(t[s]-10) , it says there is unexpected units.

Thank you very much for your reply
HUANG BO
if I want to using the 1[V] *step1(t[1/s]-10) to realize the function of increasing to 1[V] after 10 seconds rather than 10 Hz , how could I change the formula? If I put the formula 1[V]*step1(t[s]-10) , it says there is unexpected units. Thank you very much for your reply HUANG BO
Pieter Westerik
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Posted: 1 decade ago Jul 8, 2014, 6:24 a.m. EDT
Oh yes, sorry, t is already in seconds. So then the way you put it is correct I think.
Oh yes, sorry, t is already in seconds. So then the way you put it is correct I think.

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