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Using integration coupling variables as Boundary Conditions

Posted Aug 9, 2010, 9:10 a.m. EDT 4 Replies

Daniel Kappe
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Hi,

I am trying to solve a Laplace equation on a square with dirichlet boundary conditions. Therefore I calculate the boundary values with integration coupling variables defined on a previous solved PDE. The Problem is, that does not use the coupling variables or sets it to zero, while calculation the Laplace Problem.
I would like to know if there is any possibility to save my boundary values, so that I am able to use them later, or how I use the coupling variables in a second calculation.

Best regards
Daniel
4 Replies Last Post Aug 10, 2010, 10:23 a.m. EDT
Daniel Kappe
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Posted: 1 decade ago Aug 10, 2010, 8:07 a.m. EDT
Hi again,
I have solved my problem by using two dependent variables in one Applicationmode. But a new problem arised. As soon as I set the boundary contraints to the integralexpression, the solution of the first variable and the integral change their values. But there is no dependency on the second solution.

Best regards
Daniel
Hi again, I have solved my problem by using two dependent variables in one Applicationmode. But a new problem arised. As soon as I set the boundary contraints to the integralexpression, the solution of the first variable and the integral change their values. But there is no dependency on the second solution. Best regards Daniel
Danial Tz
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Posted: 1 decade ago Aug 10, 2010, 9:33 a.m. EDT

Hi again,
I have solved my problem by using two dependent variables in one Applicationmode. But a new problem arised. As soon as I set the boundary contraints to the integralexpression, the solution of the first variable and the integral change their values. But there is no dependency on the second solution.

Best regards
Daniel


Out of my topic area (sorry), but did you check the bidirectional coupling (Comsol 4)? (ideal case in 3.5a)

I remember I saw the integral coupling boundary condition with temperature in one of the Comsol 4 manuals. Can't remember where though.
[QUOTE] Hi again, I have solved my problem by using two dependent variables in one Applicationmode. But a new problem arised. As soon as I set the boundary contraints to the integralexpression, the solution of the first variable and the integral change their values. But there is no dependency on the second solution. Best regards Daniel [/QUOTE] Out of my topic area (sorry), but did you check the bidirectional coupling (Comsol 4)? (ideal case in 3.5a) I remember I saw the integral coupling boundary condition with temperature in one of the Comsol 4 manuals. Can't remember where though.
Daniel Kappe
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Posted: 1 decade ago Aug 10, 2010, 10:01 a.m. EDT
I am currently working with COMSOL 3.3
I tried to use COMSOL 4 but I am too much accustomed to 3.3 to use it.
I am currently working with COMSOL 3.3 I tried to use COMSOL 4 but I am too much accustomed to 3.3 to use it.
Danial Tz
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Posted: 1 decade ago Aug 10, 2010, 10:23 a.m. EDT

I am currently working with COMSOL 3.3
I tried to use COMSOL 4 but I am too much accustomed to 3.3 to use it.


I think it is called weak formulation, ideal-case or something like that.
[QUOTE] I am currently working with COMSOL 3.3 I tried to use COMSOL 4 but I am too much accustomed to 3.3 to use it. [/QUOTE] I think it is called weak formulation, ideal-case or something like that.

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