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Creating mesh in 3D geometry
Posted Aug 27, 2015, 2:32 p.m. EDT Version 4.4 1 Reply
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I am trying to mesh the particular geometry as attached here. Its giving me error saying 'mesh of linking face must be structured quad mesh'. Can anyone help me with this?
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1 Reply Last Post Aug 28, 2015, 2:04 a.m. EDT
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Posted:
9 years ago
Hi
you are asking for a topology incompatibility, like asking for a triangle with 4 corners, which is not possible!
I see two ways around:
a) either you replace the "Free Triangular" surface/boundary mesh by a "Free quad", and keep your mapped mesh for the three top branches boundaries, and then you sweep the full geometry once
b) you map the three branches top boundary, i.e. with a Distribution sub node for the 3 edges at the pentagon intersection region. Then you sweep these three branches through leaving the pentagon intersection region unmeshed. You then add a Mesh - More Operations - Convert node and select the three surfaces interfacing the pentagon region to the three branches. And finally you add a "Free Tetahedral" mesh for the remaining (pentagonal prism intersection region
Meshing is really "playing" with the geometry :)
--
Good luck
Ivar
you are asking for a topology incompatibility, like asking for a triangle with 4 corners, which is not possible!
I see two ways around:
a) either you replace the "Free Triangular" surface/boundary mesh by a "Free quad", and keep your mapped mesh for the three top branches boundaries, and then you sweep the full geometry once
b) you map the three branches top boundary, i.e. with a Distribution sub node for the 3 edges at the pentagon intersection region. Then you sweep these three branches through leaving the pentagon intersection region unmeshed. You then add a Mesh - More Operations - Convert node and select the three surfaces interfacing the pentagon region to the three branches. And finally you add a "Free Tetahedral" mesh for the remaining (pentagonal prism intersection region
Meshing is really "playing" with the geometry :)
--
Good luck
Ivar