Edgar J. Kaiser
Certified Consultant
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Posted:
4 years ago
Oct 20, 2020, 7:24 a.m. EDT
Guilherme,
in your model all boundaries except the heat sources are insulated. Therefore the temperature rises to infinity and breaks the solver.
You need a heat sink. This can e.g. be a temperature boundary. The heat you bring in must go out somewhere.
Cheers
Edgar
-------------------
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
Guilherme,
in your model all boundaries except the heat sources are insulated. Therefore the temperature rises to infinity and breaks the solver.
You need a heat sink. This can e.g. be a temperature boundary. The heat you bring in must go out somewhere.
Cheers
Edgar
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Posted:
4 years ago
Oct 20, 2020, 11:14 a.m. EDT
Updated:
4 years ago
Oct 20, 2020, 11:23 a.m. EDT
Dear Edgard,
Thank you for the answer. Just so I see if I understand I should set one of my edges with a heat flux Q that I want to vary from 1 to 10 W and then set my remaining boundaries to a temperature? (e.g: 25 degC)
How I would see the temperature rise caused by this Q then?
EDIT: by doing as I exemplified above I can now properly simulate. My new question now is if I can somehow evaluate the points and values of my min and max temperatures (e.g: (1,1,1, 25) where 1,1,1 would be x,y,z and 25 would be the temperature).
Dear Edgard,
Thank you for the answer. Just so I see if I understand I should set one of my edges with a heat flux Q that I want to vary from 1 to 10 W and then set my remaining boundaries to a temperature? (e.g: 25 degC)
How I would see the temperature rise caused by this Q then?
EDIT: by doing as I exemplified above I can now properly simulate. My new question now is if I can somehow evaluate the points and values of my min and max temperatures (e.g: (1,1,1, 25) where 1,1,1 would be x,y,z and 25 would be the temperature).
Edgar J. Kaiser
Certified Consultant
Please login with a confirmed email address before reporting spam
Posted:
4 years ago
Oct 20, 2020, 3:31 p.m. EDT
You can check the max/min operations in 'Nonlocal couplings' and respective Max/Min datasets in the postprocessing.
Also point probes and point cut datasets may be of interest.
Cheers
Edgar
-------------------
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
You can check the max/min operations in 'Nonlocal couplings' and respective Max/Min datasets in the postprocessing.
Also point probes and point cut datasets may be of interest.
Cheers
Edgar
Please login with a confirmed email address before reporting spam
Posted:
4 years ago
Oct 21, 2020, 6:59 a.m. EDT
Updated:
4 years ago
Oct 21, 2020, 7:13 a.m. EDT
Dear Edgar,
I actually ran the simulation and extracted the results using a Derived Value and created a Surface Maximum. However this doesn't agree with my analytical model and I am not sure if then I am correctly extracting the value. In theory my thermal resistance would be given by
which for d = 0.1mm, k = 401 and t = 1mm would yield a thermal resistance of 317 degC/W, while from simulation I get around 2degC/W.
What I am doing wrongly here?
Dear Edgar,
I actually ran the simulation and extracted the results using a **Derived Value** and created a **Surface Maximum**. However this doesn't agree with my analytical model and I am not sure if then I am correctly extracting the value. In theory my thermal resistance would be given by
R_{thermal} = \frac{t}{k_{cu}*pi*\frac{d}{4}^2}
which for d = 0.1mm, k = 401 and t = 1mm would yield a thermal resistance of 317 degC/W, while from simulation I get around 2degC/W.
What I am doing wrongly here?
Edgar J. Kaiser
Certified Consultant
Please login with a confirmed email address before reporting spam
Posted:
4 years ago
Oct 21, 2020, 11:29 a.m. EDT
Check if your model realizes this kind of thermal resistor. I think the barrel of the cylinder should be thermally isolated in this case.
-------------------
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
Check if your model realizes this kind of thermal resistor. I think the barrel of the cylinder should be thermally isolated in this case.
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Posted:
4 years ago
Oct 22, 2020, 3:10 a.m. EDT
Thank you Edgar, it seems now that this works. This is my first try with COMSOL and in my mind I was doing so (but I ovewrote the isolation by setting a temperature boundary).
Thank you Edgar, it seems now that this works. This is my first try with COMSOL and in my mind I was doing so (but I ovewrote the isolation by setting a temperature boundary).
Edgar J. Kaiser
Certified Consultant
Please login with a confirmed email address before reporting spam
Posted:
4 years ago
Oct 22, 2020, 4:14 a.m. EDT
Good to hear that it works for you now.
-------------------
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
Good to hear that it works for you now.