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Defining volume of cavity

Posted Jan 5, 2021, 8:17 a.m. EST Structural & Acoustics, General, Parameters, Variables, & Functions Version 5.3 3 Replies

Sharique Nomani
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I am solving the problem given in the following link: ( www.comsol.com/blogs/modeling-hydrostatic-pressure-fluid-deformable-container ). Can anyone please tell me how has the volume of the cavity been defined? I tried integrating with the intop1 operator (selected the boundary of the hyper-elastic material and computed with revolving geometry on), but intop1(1) gives the boundary area. If I select the domain of the balloon, it would give the volume of the material, which we don’t want, right? I'm a beginner, please help me out.

3 Replies Last Post Jan 5, 2021, 2:41 p.m. EST
Jeff Hiller COMSOL Employee

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Posted: 4 years ago Jan 5, 2021, 10:43 a.m. EST

Hello Sharique,

See https://www.comsol.com/blogs/computing-controlling-volume-cavity/ .

Best regards,

Jeff

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Jeff Hiller
Hello Sharique, See https://www.comsol.com/blogs/computing-controlling-volume-cavity/ . Best regards, Jeff
Sharique Nomani
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Posted: 4 years ago Jan 5, 2021, 2:23 p.m. EST
Updated: 4 years ago Jan 5, 2021, 2:24 p.m. EST

Thank you, Jeff.

See https://www.comsol.com/blogs/computing-controlling-volume-cavity/ .

In this model, the area of the cavity has been found. In a 2D-axisymmetric arrangement (such as the one in original query), selecting the interior boundary and choosing the 'compute with revolving geometry on' option, should give me the volume of the cavity for the expression AreaInt(-z*solid.nz), isn't it?

Thank you, Jeff. >See https://www.comsol.com/blogs/computing-controlling-volume-cavity/ . In this model, the area of the cavity has been found. In a 2D-axisymmetric arrangement (such as the one in original query), selecting the interior boundary and choosing the 'compute with revolving geometry on' option, should give me the volume of the cavity for the expression AreaInt(-z*solid.nz), isn't it?
Jeff Hiller COMSOL Employee

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Posted: 4 years ago Jan 5, 2021, 2:41 p.m. EST

That's the idea, yes. You can check your implementation by using a toy geometry for which the analytical expression of the volume is known, like a sphere, cylinder, or cone.

Best,

Jeff

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Jeff Hiller
That's the idea, yes. You can check your implementation by using a toy geometry for which the analytical expression of the volume is known, like a sphere, cylinder, or cone. Best, Jeff

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