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volume within a closed isosurface

Posted Dec 4, 2012, 9:32 p.m. EST Results & Visualization 3 Replies

Daniel Wellburn
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Hello

WIthin a 3D domain containing closed isosurfaces, is there a way to calculate the volume of material contained within each isosurface?

Many thanks

Dan
3 Replies Last Post Dec 7, 2012, 2:58 a.m. EST
Ivar KJELBERG COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)
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Posted: 1 decade ago Dec 5, 2012, 1:18 a.m. EST
Hi

if you define an integration over a domain, and use the Bolean operand "(My_Var < My_value)" I would expect to get the total volume of the region obeying the Bolean condition, no ?

In COMSOL a 3D integration is by default: integrate_over_my_selections_of_Domains(argument*dx*dy*dz)
while the dx*dy*dz is "implicit" (or it might be 2*pi*r*rd*dz in 2D axi)
--
Good luck
Ivar
Hi if you define an integration over a domain, and use the Bolean operand "(My_Var < My_value)" I would expect to get the total volume of the region obeying the Bolean condition, no ? In COMSOL a 3D integration is by default: integrate_over_my_selections_of_Domains(argument*dx*dy*dz) while the dx*dy*dz is "implicit" (or it might be 2*pi*r*rd*dz in 2D axi) -- Good luck Ivar
Daniel Wellburn
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Posted: 1 decade ago Dec 7, 2012, 1:25 a.m. EST
HI Ivar

Thanks I hadn't thought of using a boolean expression.

Works perfectly of course

Thanks again

Dan
HI Ivar Thanks I hadn't thought of using a boolean expression. Works perfectly of course Thanks again Dan
Ivar KJELBERG COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)
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Posted: 1 decade ago Dec 7, 2012, 2:58 a.m. EST
Hi

one warning, do not use Boolean on average operators, as the normalisation is not taking into account the boolean expression and you get too low values. Then its worth to write out the two integration fully, both with the same boolean expression in the numerator and de-numerator of the average expression

--
Good luck
Ivar
Hi one warning, do not use Boolean on average operators, as the normalisation is not taking into account the boolean expression and you get too low values. Then its worth to write out the two integration fully, both with the same boolean expression in the numerator and de-numerator of the average expression -- Good luck Ivar

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