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Curvature using divergence of surface normal
Posted Jul 22, 2014, 2:09 p.m. EDT Parameters, Variables, & Functions 1 Reply
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I want to calculate the curvature of a 3D surface in a 2D axisymmetric model. The variable 'curv' only gives the curvature of the curve in the 2D axisymmetric plane, not the full 3D curvature. For instance, if I were to draw a straight, sloped line in the axisymmetric plane (creating a cone), the variable 'curv' would be equal to zero.
The curvature is proportional to div(n) or, equivalently, dtang(n) where n is the unit normal to the surface. I tried to calculate these by doing d(nr*r,r)/r+d(nz,z) or dtang(nr*r)/r+dtang(nz,z) but it won't output anything. It isn't giving me an error, it just creates a blank plot when I try to plot the curvature vs. arc length of the curve.
Does anyone know what I'm doing wrong here?
Thanks
Hello TGA
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Regards,
Brandon